AP® Biology review sheet from Aim for Five (aimforfive.com/bio/units/6/6-1)
Unit 6 · Topic 6.1
6.1 DNA and RNA Structure
DNA (and, in some viruses, RNA) is the molecule that stores hereditary information. This topic covers how that information is packaged in prokaryotes and eukaryotes and why strict base pairing, a purine always with a pyrimidine, makes DNA reliable hereditary material.
Key terms
- nucleotide
- purine
- pyrimidine
- complementary base pairing
- histone
- plasmid
Where genetic information lives
Every living cell stores its genetic information in DNA, and passes it on by copying that DNA. Some viruses use RNA instead (examples include influenza and HIV), which is why the topic says hereditary information is stored in DNA and, in some cases, RNA.
How the DNA is packaged differs between the two main cell types:
- Prokaryotes (bacteria and archaea) usually have a single circular chromosome that sits in the cytoplasm in a region called the nucleoid. There's no nucleus.
- Eukaryotes have several linear chromosomes inside a nucleus. Each chromosome is one very long DNA molecule wrapped around proteins called histones, like thread around spools. This DNA–protein mix is called chromatin, and it can be packed loosely or tightly (which matters for gene expression in 6.5).
- Plasmids are small, circular, extra DNA molecules separate from the main chromosome. They're common in bacteria and also found in some eukaryotes such as yeast. Plasmids often carry useful genes, such as antibiotic resistance genes, and they're a key tool in biotechnology (6.8).
Nucleotides and the double helix
DNA and RNA are polymers of nucleotides. Each nucleotide has a five-carbon sugar (deoxyribose in DNA, ribose in RNA), a phosphate group and a nitrogenous base. The sugar of one nucleotide bonds to the phosphate of the next, forming a sugar-phosphate backbone with a 5′ end and a 3′ end.
In DNA, two strands wind into a double helix. The strands are antiparallel: one runs 5′ → 3′ and its partner runs 3′ → 5′. The bases point inward and pair by hydrogen bonds. RNA is usually single-stranded, but it can fold back on itself where bases pair, which gives molecules like tRNA their shape.
Purines, pyrimidines and base pairing
The bases come in two shapes. Purines, adenine (A) and guanine (G), have a double-ring structure. Pyrimidines, cytosine (C), thymine (T) and uracil (U), have a single ring. A purine always pairs with a pyrimidine, which keeps the helix the same width all the way along.
The specific pairs are A with T (A with U in RNA) and G with C. G–C pairs form three hydrogen bonds and A–T pairs form two. Because the pairing is so specific, each strand's sequence determines its partner's, so either strand can serve as a template for an exact copy. These pairing rules are the same in all known life, which is part of the evidence for common ancestry.
| Feature | DNA | RNA |
|---|---|---|
| Sugar | Deoxyribose | Ribose |
| Bases | A, T, G, C | A, U, G, C |
| Usual structure | Double-stranded helix | Single-stranded, can fold |
| Main job | Long-term storage of genetic information | Carries and uses the information (mRNA, tRNA, rRNA); genome in some viruses |
Using base-pairing rules
In double-stranded DNA, every A is paired with a T and every G with a C. So the amount of A equals the amount of T, and the amount of G equals the amount of C. If you know the percentage of one base, you can work out all four. This shortcut works only for double-stranded DNA; a single-stranded RNA molecule has no partner strand, so its A and U don't have to match.
Worked examples
Try each one yourself first, then open the solution.
- Example 1
Base percentages from one value
A sample of double-stranded DNA is 30% adenine. What percentages of thymine, guanine and cytosine does it contain?
Show the solutionHide the solution
- Step 1: Each A pairs with a T, so T = A = 30%.
- Step 2: A + T = 60%, so G + C = 100% − 60% = 40%.
- Step 3: Each G pairs with a C, so G = C = 40% ÷ 2 = 20%.
Answer: Thymine 30%, guanine 20%, cytosine 20%.
- Example 2
Writing the complementary strand
One strand of DNA reads 5′-GATTACCA-3′. Write the complementary strand, labeling its 5′ and 3′ ends, and then write it in the 5′ → 3′ direction.
Show the solutionHide the solution
- Step 1: Pair each base: G→C, A→T, T→A, T→A, A→T, C→G, C→G, A→T.
- Step 2: The strands are antiparallel, so the partner strand runs the opposite way: 3′-CTAATGGT-5′, lined up under the original.
- Step 3: Read it backward to write it 5′ → 3′: 5′-TGGTAATC-3′.
- Step 4: A common trap is writing 5′-CTAATGGT-3′, which gets the bases right but the direction wrong.
Answer: 3′-CTAATGGT-5′, which is the same strand as 5′-TGGTAATC-3′.
Common mistakes
- Applying A = T and G = C to single-stranded RNA or single-stranded viral genomes. The rule depends on a complementary partner strand.
- Swapping purines and pyrimidines. Purines (A, G) are the double-ring bases; pyrimidines (C, T, U) are single-ring.
- Writing a complementary strand in the same direction as the original. Strands are antiparallel, so label the 5′ and 3′ ends.
- Saying prokaryotes have no DNA organization or no plasmids, or that only bacteria have plasmids. Both prokaryotes and some eukaryotes can carry plasmids.
On the exam
- Expect questions comparing prokaryotic and eukaryotic genomes (circular vs. linear, histones, plasmids) or comparing DNA and RNA structure.
- If asked why DNA works as hereditary material, connect specific base pairing to accurate copying: each strand is a template for its partner.
Connected topics
Videos
Check yourself
5 questions on 6.1 DNA and RNA Structure. Pick an answer to see if you got it, and why.
The double helix of DNA has a nearly uniform width along its entire length. Which feature of DNA best explains this?
Histone proteins are rich in positively charged amino acids. Which of the following best explains why this helps histones bind DNA?
A bacterium carries a gene for antibiotic resistance on a small circular DNA molecule separate from its main chromosome. Which of the following best describes this molecule and its genome?
| Sample | A (%) | G (%) | C (%) | T (%) | U (%) |
|---|---|---|---|---|---|
| 1 | 29 | 21 | 21 | 29 | 0 |
| 2 | 24 | 18 | 26 | 32 | 0 |
| 3 | 26 | 24 | 24 | 0 | 26 |
Experimental data: percent of each base in the genetic material of three different viruses
Which of the following best describes the genetic material of the virus in Sample 2?
Which of the following best describes the genetic material of the virus in Sample 3?
0 of 5 answered