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2027 exam · Formula sheet

AP® Statistics formula sheet (2027), explained

The official reference information for AP Statistics has three parts: a guide to typing statistics notation in your free-response answers, two pages of formulas (descriptive statistics, probability and distributions, and sampling distributions and inference) and three tables (standard normal probabilities, t critical values and chi-square critical values). This page goes through every formula and table: what each symbol means, when to use it, the mistake students make most often and which topic teaches it. At the bottom is a list of what you still have to know by heart, because the sheet leaves it out.

The official sheet: AP Statistics Exam Reference Information (PDF, College Board) (opens in a new tab). Keep it open next to this page. We link to it instead of copying it, so you always see College Board's current version.

Checked against the 2027 version on October 5, 2026. The explanations are ours, not College Board's.

Using the sheet on exam day

  • The exam is fully digital for 2027, and the formula sheet and tables are available in the testing app. Look through them before exam day so you know where each formula and table is and don't lose time hunting for it.
  • In free-response answers you can use the testing app's toolbar for symbols, or type keyboard versions: x-bar for xˉ\bar{x}, p-hat for p^\hat{p}, mu for μ\mu, sigma for σ\sigma, alpha for α\alpha, H_0 and H_a for the hypotheses, and an underscore for a subscript, like p-hat_1 or mu_A.
  • To show a calculation, type it the way you'd enter it in a calculator: ^ for a power, sqrt() for a square root, +/- for ±\pm, <= and >= for ≤\le and ≥\ge, and != for ≠\ne. For example, a binomial probability can be typed as 10*(0.3)^2*(0.7)^3, and an interval as 0.62+/-1.96*sqrt(0.62*0.38/400). Write a finished interval as (0.572, 0.668) or "0.572 to 0.668".
  • The sheet asks you to show your work on every free-response question. Write the formula with your numbers plugged in, not just the final answer or a calculator command.
  • The sheet never tells you which procedure to use, which conditions to check or how many degrees of freedom to use. It also doesn't list common critical values, but the last row of Table B (df = ∞) gives the normal ones: z∗=1.645z^* = 1.645 for 90%, 1.960 for 95% and 2.576 for 99%.

Descriptive statistics

Summaries of one quantitative variable, and the form of a regression line.

Sample mean

xˉ=1n∑xi=∑xin\displaystyle \bar{x} = \frac{1}{n}\sum x_i = \frac{\sum x_i}{n}

What the symbols mean

xˉ\bar{x}
the sample mean (read "x-bar")
Unit: same units as the data
xix_i
each data value in the sample
Unit: same units as the data
nn
the number of values in the sample
Unit: none (a count)
∑\sum
add up every value that follows
Unit: none

Use it when: Use it when you have a list of data values and need the average, the usual measure of center for a roughly symmetric distribution.

Watch out: Reporting the mean as the center of a strongly skewed distribution or one with outliers. The mean gets pulled toward the tail, so use the median there.

Learn it: 1.7 Summary Statistics for One Quantitative Variable

Sample standard deviation

s=1n−1∑(xi−xˉ)2=∑(xi−xˉ)2n−1\displaystyle s = \sqrt{\frac{1}{n-1}\sum\left(x_i - \bar{x}\right)^2} = \sqrt{\frac{\sum\left(x_i - \bar{x}\right)^2}{n-1}}

What the symbols mean

ss
the sample standard deviation: a typical distance between the data values and their mean
Unit: same units as the data
xi−xˉx_i - \bar{x}
the deviation of one value from the mean
Unit: same units as the data
n−1n - 1
the sample size minus one
Unit: none

Use it when: Use it to measure the spread of sample data around the mean. Square each deviation, add them, divide by n−1n - 1 and take the square root.

Watch out: Dividing by nn instead of n−1n - 1, or stopping before the square root. Without the root you have the variance, which is in squared units of the data.

Try it: Find the mean and standard deviation of the sample 2, 4, 6, 8.

Answer: xˉ=20/4=5\bar{x} = 20/4 = 5. The deviations are −3, −1, 1, 3, whose squares add to 20. Then s=20/3≈2.58s = \sqrt{20/3} \approx 2.58.

Learn it: 1.7 Summary Statistics for One Quantitative Variable

Least-squares regression line

y^=a+bx\displaystyle \hat{y} = a + bx

What the symbols mean

y^\hat{y}
the predicted value of the response variable (read "y-hat")
Unit: units of y
aa
the y-intercept: the predicted y when x = 0
Unit: units of y
bb
the slope: the predicted change in y for each one-unit increase in x
Unit: units of y per unit of x
xx
the value of the explanatory variable
Unit: units of x

Use it when: Use it to predict a response from an explanatory value once you have a and b, usually from technology or computer output. You also interpret b and a in context.

Watch out: Writing the line with yy instead of y^\hat{y}, or interpreting the slope as a certain change. It's a predicted change, on average, and only within the range of the data.

Try it: A line is y^=12+3.5x\hat{y} = 12 + 3.5x. Predict y when x = 4. If the actual y is 29, what's the residual?

Answer: y^=12+3.5(4)=26\hat{y} = 12 + 3.5(4) = 26. The residual is y−y^=29−26=3y - \hat{y} = 29 - 26 = 3, so the point is 3 units above the line.

Learn it: 5.3 Linear Regression Models · 5.5 Least-Squares Regression

Probability

Two rules for combining events.

Addition rule for A or B

P(A∪B)=P(A)+P(B)−P(A∩B)\displaystyle P\left(A \cup B\right) = P\left(A\right) + P\left(B\right) - P\left(A \cap B\right)

What the symbols mean

P(A∪B)P\left(A \cup B\right)
the probability that A or B (or both) happens
Unit: none
P(A∩B)P\left(A \cap B\right)
the probability that A and B both happen
Unit: none

Use it when: Use it when a question asks for the probability of "A or B" and you know (or can find) each probability and the probability of both.

Watch out: Forgetting to subtract P(A∩B)P(A \cap B), which counts the overlap twice. You can skip that term only when A and B are mutually exclusive, since then P(A∩B)=0P(A \cap B) = 0.

Try it: P(A)=0.5P(A) = 0.5, P(B)=0.4P(B) = 0.4 and P(A∩B)=0.2P(A \cap B) = 0.2. Find P(A∪B)P(A \cup B) and P(A∣B)P(A \mid B).

Answer: P(A∪B)=0.5+0.4−0.2=0.7P(A \cup B) = 0.5 + 0.4 - 0.2 = 0.7. P(A∣B)=0.2/0.4=0.5P(A \mid B) = 0.2/0.4 = 0.5. That equals P(A)P(A), so A and B are independent.

Learn it: 2.7 Independent Events and Unions of Events · 2.5 Mutually Exclusive Events

Conditional probability

P(A∣B)=P(A∩B)P(B)\displaystyle P\left(A \mid B\right) = \frac{P\left(A \cap B\right)}{P\left(B\right)}

What the symbols mean

P(A∣B)P\left(A \mid B\right)
the probability of A given that B happened
Unit: none
P(B)P\left(B\right)
the probability of the condition, B
Unit: none

Use it when: Use it for "given that" questions, or to check independence: A and B are independent when P(A∣B)=P(A)P(A \mid B) = P(A). With a two-way table, you can also just divide within the row or column for B.

Watch out: Dividing by the wrong event. The event after the bar, the one you're told happened, always goes in the denominator, so P(A∣B)P(A \mid B) and P(B∣A)P(B \mid A) are usually different.

Learn it: 2.6 Conditional Probability · 2.7 Independent Events and Unions of Events

Probability distributions

The mean and standard deviation of a discrete random variable, and the binomial distribution.

Mean of a discrete random variable

μX=E(X)=∑xi⋅P(xi)\displaystyle \mu_X = E\left(X\right) = \sum x_i \cdot P\left(x_i\right)

What the symbols mean

μX\mu_X
the mean of the random variable X
Unit: same units as X
E(X)E\left(X\right)
the expected value of X, another name for its mean
Unit: same units as X
xix_i
each possible value of X
Unit: same units as X
P(xi)P\left(x_i\right)
the probability of that value
Unit: none

Use it when: Use it when you have a probability distribution table and need the long-run average outcome.

Watch out: Averaging the values without weighting them by their probabilities, or saying the mean is the most likely outcome. It's the average over many, many trials.

Learn it: 2.9 Parameters of Random Variables · 2.8 Introduction to Random Variables and Probability Distributions

Standard deviation of a discrete random variable

σX=∑(xi−μX)2⋅P(xi)\displaystyle \sigma_X = \sqrt{\sum\left(x_i - \mu_X\right)^2 \cdot P\left(x_i\right)}

What the symbols mean

σX\sigma_X
the standard deviation of X: how much outcomes typically vary from the mean
Unit: same units as X
xi−μXx_i - \mu_X
how far one possible value is from the mean
Unit: same units as X
P(xi)P\left(x_i\right)
the probability of that value
Unit: none

Use it when: Use it with a probability distribution table to find the spread of the outcomes. Find μX\mu_X first.

Watch out: Forgetting the square root (that's the variance) or forgetting to multiply each squared deviation by its probability. There's no n−1n - 1 here.

Try it: X takes the values 0, 1, 2, 3 with probabilities 0.1, 0.3, 0.4, 0.2. Find μX\mu_X and σX\sigma_X.

Answer: μX=0(0.1)+1(0.3)+2(0.4)+3(0.2)=1.7\mu_X = 0(0.1) + 1(0.3) + 2(0.4) + 3(0.2) = 1.7. The weighted squared deviations are 0.289, 0.147, 0.036 and 0.338, which add to 0.81, so σX=0.81=0.9\sigma_X = \sqrt{0.81} = 0.9.

Learn it: 2.9 Parameters of Random Variables

Binomial probability

P(X=x)=(nx)px(1−p)n−x,where x=0,1,2,3,…,n\displaystyle P\left(X = x\right) = \binom{n}{x} p^x \left(1 - p\right)^{n-x}, \quad \text{where } x = 0, 1, 2, 3, \ldots, n

What the symbols mean

XX
the number of successes in n trials
Unit: none (a count)
xx
the particular number of successes you want
Unit: none (a count)
nn
the number of trials
Unit: none (a count)
pp
the probability of success on each trial
Unit: none
(nx)\binom{n}{x}
the number of ways to arrange x successes among n trials ("n choose x")
Unit: none

Use it when: Use it for the probability of exactly x successes when there's a fixed number of independent trials, each a success or failure with the same p. For "at most" or "at least", add several of these, or use a cumulative calculator command.

Watch out: Using it when the conditions fail, for example drawing without replacement from a small group, so the trials aren't independent. Also, "at least 1" is easiest as 1−P(X=0)1 - P(X = 0).

Try it: A free throw goes in with probability 0.3. In 5 independent shots, find P(X=2)P(X = 2).

Answer: (52)(0.3)2(0.7)3=10(0.09)(0.343)≈0.309\binom{5}{2}(0.3)^2(0.7)^3 = 10(0.09)(0.343) \approx 0.309.

Learn it: 2.10 The Binomial Distribution

Mean of a binomial random variable

μX=np\displaystyle \mu_X = np

What the symbols mean

μX\mu_X
the mean number of successes
Unit: none (a count)
nn
the number of trials
Unit: none (a count)
pp
the probability of success on each trial
Unit: none

Use it when: Use it for the expected number of successes in a binomial setting, instead of the long sum.

Watch out: Using it for a variable that isn't binomial. Check that n is fixed, trials are independent and p is the same every time.

Learn it: 2.10 The Binomial Distribution

Standard deviation of a binomial random variable

σX=np(1−p)\displaystyle \sigma_X = \sqrt{np\left(1 - p\right)}

What the symbols mean

σX\sigma_X
the standard deviation of the number of successes
Unit: none (a count)
1−p1 - p
the probability of failure on each trial
Unit: none

Use it when: Use it for the spread of the number of successes in a binomial setting.

Watch out: Leaving off the square root and reporting np(1−p)np(1 - p), which is the variance.

Try it: For 50 shots with p=0.3p = 0.3, find the mean and standard deviation of the number made.

Answer: μX=50(0.3)=15\mu_X = 50(0.3) = 15 shots and σX=50(0.3)(0.7)=10.5≈3.24\sigma_X = \sqrt{50(0.3)(0.7)} = \sqrt{10.5} \approx 3.24 shots.

Learn it: 2.10 The Binomial Distribution

Sampling distributions and inferential statistics

The two patterns every z, t test and interval follows. The tables below fill in the standard error.

Standardized test statistic

test statistic=statistic−parameterstandard error of the statistic\displaystyle \text{test statistic} = \frac{\text{statistic} - \text{parameter}}{\text{standard error of the statistic}}

What the symbols mean

statistic\text{statistic}
the value from your sample, like p^\hat{p} or xˉ\bar{x}
Unit: units of the statistic
parameter\text{parameter}
the value the null hypothesis claims, like p0p_0 or μ0\mu_0
Unit: units of the statistic
standard error of the statistic\text{standard error of the statistic}
how much the statistic typically varies from sample to sample
Unit: units of the statistic

Use it when: Use it in a significance test to find z or t: how many standard errors your statistic is from the null value. Then find the p-value from Table A (z) or Table B (t).

Watch out: Plugging in the sample statistic where the null value goes, or using the wrong spread. For a one-proportion z test, the denominator uses p0p_0: p0(1−p0)/n\sqrt{p_0(1 - p_0)/n}, not p^\hat{p}.

Try it: Test H0:p=0.5H_0: p = 0.5 against Ha:p>0.5H_a: p > 0.5 with n=100n = 100 and p^=0.58\hat{p} = 0.58.

Answer: The standard error under H0H_0 is 0.5(0.5)/100=0.05\sqrt{0.5(0.5)/100} = 0.05, so z=(0.58−0.5)/0.05=1.60z = (0.58 - 0.5)/0.05 = 1.60. Table A gives 0.9452 to the left, so the p-value is 1−0.9452≈0.0551 - 0.9452 \approx 0.055.

Learn it: 3.7 Carrying Out a Test for a Population Proportion · 4.5 Carrying Out a Test for a Population Mean or Population Mean Difference · 3.13 Carrying Out a Test for the Difference Between Two Population Proportions

Confidence interval

confidence interval=statistic±(critical value)⋅(standard error of the statistic)\displaystyle \text{confidence interval} = \text{statistic} \pm \left(\text{critical value}\right) \cdot \left(\text{standard error of the statistic}\right)

What the symbols mean

statistic\text{statistic}
the point estimate from your sample, like p^\hat{p} or xˉ\bar{x}
Unit: units of the statistic
critical value\text{critical value}
z∗z^* or t∗t^* for your confidence level, from Table A or Table B
Unit: none
standard error of the statistic\text{standard error of the statistic}
the estimated standard deviation of the statistic, computed from sample data
Unit: units of the statistic

Use it when: Use it to estimate a parameter. The part after ±\pm is the margin of error. Pick the standard error from the tables below to match your parameter.

Watch out: Using z∗z^* for a mean when σ\sigma is unknown (use t∗t^*), or using a test statistic like 1.60 as the critical value. The critical value comes only from the confidence level (and df).

Try it: In a random sample of 400, p^=0.62\hat{p} = 0.62. Build a 95% confidence interval for p.

Answer: SE=0.62(0.38)/400≈0.0243SE = \sqrt{0.62(0.38)/400} \approx 0.0243, and z∗=1.96z^* = 1.96, so the margin of error is about 0.048. The interval is 0.62±0.0480.62 \pm 0.048, or about (0.572, 0.668).

Learn it: 3.3 Constructing a Confidence Interval for a Population Proportion · 4.2 Constructing a Confidence Interval for a Population Mean or Population Mean Difference · 4.7 Constructing a Confidence Interval for the Difference Between Two Population Means

Sampling distributions for proportions

Standard deviation columns use the true parameter p. Standard error columns use the sample's p^\hat{p}, because in practice you don't know p.

Mean of a sample proportion

μp^=p\displaystyle \mu_{\hat{p}} = p

What the symbols mean

μp^\mu_{\hat{p}}
the mean of the sampling distribution of p^\hat{p}
Unit: none
pp
the true population proportion
Unit: none

Use it when: Use it to describe the center of the sampling distribution of p^\hat{p}. It says p^\hat{p} is an unbiased estimator of p.

Watch out: Saying any one sample's p^\hat{p} equals p. Only the average of p^\hat{p} over all possible samples equals p.

Learn it: 3.2 Sampling Distributions for Sample Proportions · 3.1 Estimators

Standard deviation of a sample proportion

σp^=p(1−p)n\displaystyle \sigma_{\hat{p}} = \sqrt{\frac{p\left(1 - p\right)}{n}}

What the symbols mean

σp^\sigma_{\hat{p}}
the standard deviation of p^\hat{p} from sample to sample
Unit: none
pp
the true (or claimed) population proportion
Unit: none
nn
the sample size
Unit: none (a count)

Use it when: Use it when p is known or assumed: in probability questions about p^\hat{p}, and in a one-proportion z test, where you use the null value p0p_0.

Watch out: Using it without checking the 10% condition (n≤0.10Nn \le 0.10N) when sampling without replacement. Also, larger samples shrink it by a factor of n\sqrt{n}, so 4 times the sample size halves it.

Try it: If p=0.30p = 0.30 and n=200n = 200, what is σp^\sigma_{\hat{p}}?

Answer: σp^=0.30(0.70)/200≈0.032\sigma_{\hat{p}} = \sqrt{0.30(0.70)/200} \approx 0.032.

Learn it: 3.2 Sampling Distributions for Sample Proportions · 3.7 Carrying Out a Test for a Population Proportion

Standard error of a sample proportion

SEp^=p^(1−p^)n\displaystyle SE_{\hat{p}} = \sqrt{\frac{\hat{p}\left(1 - \hat{p}\right)}{n}}

What the symbols mean

SEp^SE_{\hat{p}}
the estimated standard deviation of p^\hat{p}
Unit: none
p^\hat{p}
the sample proportion (read "p-hat")
Unit: none

Use it when: Use it in a one-proportion z interval, when you don't know p and have to estimate the spread from your sample.

Watch out: Mixing it up with σp^\sigma_{\hat{p}}. Intervals use p^\hat{p} in the standard error; a one-proportion test uses p0p_0.

Learn it: 3.3 Constructing a Confidence Interval for a Population Proportion

Mean of a difference in sample proportions

μp^1−p^2=p1−p2\displaystyle \mu_{\hat{p}_1 - \hat{p}_2} = p_1 - p_2

What the symbols mean

p^1−p^2\hat{p}_1 - \hat{p}_2
the difference between the two sample proportions
Unit: none
p1−p2p_1 - p_2
the difference between the two population proportions
Unit: none

Use it when: Use it to describe the center of the sampling distribution of p^1−p^2\hat{p}_1 - \hat{p}_2, with two independent samples or two groups in an experiment.

Watch out: Switching the order partway through. Decide which group is 1 and which is 2, and keep that order in the hypotheses, the statistic and the conclusion.

Learn it: 3.9 Sampling Distributions for the Difference Between Sample Proportions

Standard deviation of a difference in sample proportions

σp^1−p^2=p1(1−p1)n1+p2(1−p2)n2\displaystyle \sigma_{\hat{p}_1 - \hat{p}_2} = \sqrt{\frac{p_1\left(1 - p_1\right)}{n_1} + \frac{p_2\left(1 - p_2\right)}{n_2}}

What the symbols mean

p1,p2p_1, p_2
the true proportions in populations 1 and 2
Unit: none
n1,n2n_1, n_2
the two sample sizes
Unit: none (a count)

Use it when: Use it when the true proportions are known, to find probabilities about the difference p^1−p^2\hat{p}_1 - \hat{p}_2.

Watch out: Subtracting under the root because the statistic is a difference. The variances always add: each sample adds its own chance variation.

Learn it: 3.9 Sampling Distributions for the Difference Between Sample Proportions

Standard error of a difference in sample proportions

SEp^1−p^2=p^1(1−p^1)n1+p^2(1−p^2)n2\displaystyle SE_{\hat{p}_1 - \hat{p}_2} = \sqrt{\frac{\hat{p}_1\left(1 - \hat{p}_1\right)}{n_1} + \frac{\hat{p}_2\left(1 - \hat{p}_2\right)}{n_2}}

What the symbols mean

p^1,p^2\hat{p}_1, \hat{p}_2
the two sample proportions
Unit: none
n1,n2n_1, n_2
the two sample sizes
Unit: none (a count)

Use it when: Use it in a two-proportion z interval for p1−p2p_1 - p_2. Each sample keeps its own p^\hat{p}, with no pooling.

Watch out: Using the pooled version for a confidence interval. An interval doesn't assume p1=p2p_1 = p_2, so it uses this unpooled standard error.

Try it: 60 of 200 people in group 1 and 50 of 250 in group 2 say yes. Build a 95% interval for p1−p2p_1 - p_2.

Answer: p^1=0.30\hat{p}_1 = 0.30 and p^2=0.20\hat{p}_2 = 0.20. SE=0.30(0.70)/200+0.20(0.80)/250≈0.0411SE = \sqrt{0.30(0.70)/200 + 0.20(0.80)/250} \approx 0.0411, so the interval is 0.10±1.96(0.0411)0.10 \pm 1.96(0.0411), about (0.019, 0.181).

Learn it: 3.10 Constructing a Confidence Interval for the Difference Between Two Population Proportions

Pooled standard error for two proportions

SEp^1−p^2=p^c(1−p^c)1n1+1n2,where p^c=n1p^1+n2p^2n1+n2\displaystyle SE_{\hat{p}_1 - \hat{p}_2} = \sqrt{\hat{p}_c\left(1 - \hat{p}_c\right)}\sqrt{\frac{1}{n_1} + \frac{1}{n_2}}, \quad \text{where } \hat{p}_c = \frac{n_1\hat{p}_1 + n_2\hat{p}_2}{n_1 + n_2}

What the symbols mean

p^c\hat{p}_c
the combined (pooled) proportion: all successes from both samples over the total sample size
Unit: none
n1p^1+n2p^2n_1\hat{p}_1 + n_2\hat{p}_2
the total number of successes in both samples
Unit: none (a count)
n1+n2n_1 + n_2
the total number of individuals in both samples
Unit: none (a count)

Use it when: The sheet labels this one "when p1=p2p_1 = p_2 is assumed". That's only the two-proportion z test with H0:p1=p2H_0: p_1 = p_2, never an interval: if the null is true, both samples estimate the same p, so you combine them.

Watch out: Averaging p^1\hat{p}_1 and p^2\hat{p}_2 to get p^c\hat{p}_c when the sample sizes differ. Add the successes and divide by the total, which is what the formula does.

Try it: With the same data (60 of 200 and 50 of 250), test H0:p1=p2H_0: p_1 = p_2 against Ha:p1>p2H_a: p_1 > p_2.

Answer: p^c=110/450≈0.244\hat{p}_c = 110/450 \approx 0.244, and SE=0.244(0.756)1/200+1/250≈0.0408SE = \sqrt{0.244(0.756)}\sqrt{1/200 + 1/250} \approx 0.0408. Then z=0.10/0.0408≈2.45z = 0.10/0.0408 \approx 2.45, and Table A gives 0.9929 to the left, so the p-value is about 0.007.

Learn it: 3.12 Setting Up a Test for the Difference Between Two Population Proportions · 3.13 Carrying Out a Test for the Difference Between Two Population Proportions

Sampling distributions for means

As with proportions, standard deviations use the population's σ\sigma and standard errors use the sample's s.

Mean of a sample mean

μxˉ=μ\displaystyle \mu_{\bar{x}} = \mu

What the symbols mean

μxˉ\mu_{\bar{x}}
the mean of the sampling distribution of xˉ\bar{x}
Unit: same units as the data
μ\mu
the population mean
Unit: same units as the data

Use it when: Use it to describe the center of the sampling distribution of xˉ\bar{x}. It says xˉ\bar{x} is an unbiased estimator of μ\mu.

Watch out: Confusing the distribution of individual values with the distribution of sample means. They have the same center but different spreads and possibly different shapes.

Learn it: 4.1 Sampling Distributions for Sample Means

Standard deviation of a sample mean

σxˉ=σn\displaystyle \sigma_{\bar{x}} = \frac{\sigma}{\sqrt{n}}

What the symbols mean

σxˉ\sigma_{\bar{x}}
the standard deviation of xˉ\bar{x} from sample to sample
Unit: same units as the data
σ\sigma
the population standard deviation
Unit: same units as the data
nn
the sample size
Unit: none (a count)

Use it when: Use it when σ\sigma is known, to find probabilities about a sample mean. If the population is normal, or n is large (the central limit theorem), xˉ\bar{x} is approximately normal.

Watch out: Using σ\sigma instead of σ/n\sigma/\sqrt{n} when the question is about the mean of a sample rather than one individual.

Try it: A population has σ=15\sigma = 15. What is the standard deviation of xˉ\bar{x} for samples of 25?

Answer: σxˉ=15/25=3\sigma_{\bar{x}} = 15/\sqrt{25} = 3, in the same units as the data.

Learn it: 4.1 Sampling Distributions for Sample Means · 2.12 Sampling Distributions and the Central Limit Theorem

Standard error of a sample mean

SExˉ=sn\displaystyle SE_{\bar{x}} = \frac{s}{\sqrt{n}}

What the symbols mean

SExˉSE_{\bar{x}}
the estimated standard deviation of xˉ\bar{x}
Unit: same units as the data
ss
the sample standard deviation
Unit: same units as the data

Use it when: Use it in one-sample t intervals and tests for μ\mu, and for a mean difference with paired data (where s and n come from the list of differences). Use df=n−1df = n - 1.

Watch out: Treating paired data as two independent samples. If each pair is measured twice, find the differences first and use this formula on them.

Try it: A random sample of 16 has xˉ=52\bar{x} = 52 and s=8s = 8. Build a 95% confidence interval for μ\mu.

Answer: SE=8/16=2SE = 8/\sqrt{16} = 2. With df=15df = 15, Table B gives t∗=2.131t^* = 2.131, so the interval is 52±2.131(2)=52±4.26252 \pm 2.131(2) = 52 \pm 4.262, about (47.74, 56.26).

Learn it: 4.2 Constructing a Confidence Interval for a Population Mean or Population Mean Difference · 4.5 Carrying Out a Test for a Population Mean or Population Mean Difference

Mean of a difference in sample means

μxˉ1−xˉ2=μ1−μ2\displaystyle \mu_{\bar{x}_1 - \bar{x}_2} = \mu_1 - \mu_2

What the symbols mean

xˉ1−xˉ2\bar{x}_1 - \bar{x}_2
the difference between the two sample means
Unit: same units as the data
μ1−μ2\mu_1 - \mu_2
the difference between the two population means
Unit: same units as the data

Use it when: Use it to describe the center of the sampling distribution of xˉ1−xˉ2\bar{x}_1 - \bar{x}_2, with two independent samples or two groups in an experiment.

Watch out: Using it for paired data. Paired data give one list of differences, so use the one-sample formulas instead.

Learn it: 4.6 Sampling Distributions for the Difference Between Two Sample Means

Standard deviation of a difference in sample means

σxˉ1−xˉ2=σ12n1+σ22n2\displaystyle \sigma_{\bar{x}_1 - \bar{x}_2} = \sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2}}

What the symbols mean

σ1,σ2\sigma_1, \sigma_2
the two population standard deviations
Unit: same units as the data
n1,n2n_1, n_2
the two sample sizes
Unit: none (a count)

Use it when: Use it when both population standard deviations are known, to find probabilities about xˉ1−xˉ2\bar{x}_1 - \bar{x}_2.

Watch out: Adding or subtracting the standard deviations themselves. Square each, divide by its n, add (never subtract), then take the square root.

Learn it: 4.6 Sampling Distributions for the Difference Between Two Sample Means

Standard error of a difference in sample means

SExˉ1−xˉ2=s12n1+s22n2\displaystyle SE_{\bar{x}_1 - \bar{x}_2} = \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}}

What the symbols mean

s1,s2s_1, s_2
the two sample standard deviations
Unit: same units as the data
n1,n2n_1, n_2
the two sample sizes
Unit: none (a count)

Use it when: Use it in two-sample t intervals and tests for μ1−μ2\mu_1 - \mu_2. Get the degrees of freedom from technology.

Watch out: Forgetting to square s, or adding s1/n1s_1/\sqrt{n_1} and s2/n2s_2/\sqrt{n_2} directly. Variances add, standard deviations don't.

Try it: Sample 1 has s1=10s_1 = 10 and n1=25n_1 = 25. Sample 2 has s2=12s_2 = 12 and n2=36n_2 = 36. Find the standard error of xˉ1−xˉ2\bar{x}_1 - \bar{x}_2.

Answer: SE=102/25+122/36=4+4≈2.83SE = \sqrt{10^2/25 + 12^2/36} = \sqrt{4 + 4} \approx 2.83, in the units of the data.

Learn it: 4.7 Constructing a Confidence Interval for the Difference Between Two Population Means · 4.10 Carrying Out a Test for the Difference Between Two Population Means

Chi-square statistic

For two-way tables of counts: tests for homogeneity and for independence.

Chi-square statistic

χ2=∑(observed−expected)2expected\displaystyle \chi^2 = \sum\frac{\left(\text{observed} - \text{expected}\right)^2}{\text{expected}}

What the symbols mean

χ2\chi^2
the chi-square statistic: how far the observed counts are from what the null hypothesis predicts
Unit: none
observed\text{observed}
the observed count: the actual count in one cell of the table
Unit: none (a count)
expected\text{expected}
the expected count: the count you'd expect in that cell if the null hypothesis were true
Unit: none (a count)

Use it when: Use it in a chi-square test for homogeneity or independence. Add one term for every cell, then find the p-value from Table C with df=(r−1)(c−1)df = (r - 1)(c - 1).

Watch out: Using proportions or percents instead of counts, or forgetting to square. The expected count, not the observed count, goes in the denominator.

Try it: Group A: 30 yes and 70 no. Group B: 50 yes and 50 no. Find χ2\chi^2 and the p-value.

Answer: Expected counts are 40 yes and 60 no in each group. χ2=100/40+100/60+100/40+100/60≈8.33\chi^2 = 100/40 + 100/60 + 100/40 + 100/60 \approx 8.33 with df=1df = 1. In Table C, 8.33 is between 7.88 and 9.14, so 0.0025<p<0.0050.0025 < p < 0.005.

Learn it: 3.14 Setting Up a Chi-Square Test for Homogeneity or Independence · 3.15 Carrying Out a Chi-Square Test for Homogeneity or Independence

Tables

Three tables of probabilities and critical values. Technology gives the same numbers more precisely.

Table A: standard normal probabilities

area to the left of z=P(Z<z)\displaystyle \text{area to the left of } z = P\left(Z < z\right)

What the symbols mean

ZZ
a standard normal random variable, with mean 0 and standard deviation 1
Unit: none
zz
a z-score, found from the row (ones and tenths) and column (hundredths)
Unit: none

Use it when: Each entry is the area to the left of z. Use it for normal probabilities, p-values for z tests, and (reading it backward) to find z∗z^* or a percentile.

Watch out: Forgetting the table only gives area to the left. For "greater than", subtract from 1, and for a two-sided p-value, double the tail area.

Try it: Find P(Z<−1.96)P(Z < -1.96) and P(Z>1.60)P(Z > 1.60).

Answer: Row −1.9, column .06 gives 0.0250. Row 1.6, column .00 gives 0.9452, so P(Z>1.60)=1−0.9452=0.0548P(Z > 1.60) = 1 - 0.9452 = 0.0548.

Learn it: 2.11 The Normal Distribution · 3.6 p-Values · 3.7 Carrying Out a Test for a Population Proportion

Table B: t distribution critical values

area to the right of t∗=p\displaystyle \text{area to the right of } t^* = p

What the symbols mean

t∗t^*
the critical value: probability p lies above it, and probability C lies between −t∗-t^* and t∗t^*
Unit: none
pp
the tail probability, listed across the top
Unit: none
CC
the confidence level, listed across the bottom
Unit: none
dfdf
degrees of freedom, one per row, going up to 1000 and ∞
Unit: none

Use it when: Use it to find t∗t^* for a confidence interval (read the confidence level at the bottom) or to bracket a p-value for a t test (find where your t falls in the df row). The ∞ row gives the z∗z^* values.

Watch out: Reading the wrong column: the top row is one tail's probability, not the confidence level. If your df isn't listed, use the next smaller df.

Try it: Find t∗t^* for a 95% interval with df=15df = 15, and the matching z∗z^*.

Answer: Row 15, column .025 (95% at the bottom) gives t∗=2.131t^* = 2.131. The ∞ row in the same column gives z∗=1.960z^* = 1.960.

Learn it: 4.2 Constructing a Confidence Interval for a Population Mean or Population Mean Difference · 4.5 Carrying Out a Test for a Population Mean or Population Mean Difference · 4.7 Constructing a Confidence Interval for the Difference Between Two Population Means

Table C: chi-square critical values

area to the right of χ2=p\displaystyle \text{area to the right of } \chi^2 = p

What the symbols mean

χ2\chi^2
the critical value with probability p above it
Unit: none
pp
the tail probability, listed across the top
Unit: none
dfdf
degrees of freedom, one per row
Unit: none

Use it when: Use it to bracket the p-value for a chi-square test. Find your df row, then see which two critical values your χ2\chi^2 falls between.

Watch out: Doubling the p-value. A chi-square test only uses the right tail, so the column heading is already the p-value bound.

Try it: What χ2\chi^2 value is needed to reject at α=0.05\alpha = 0.05 with df=2df = 2?

Answer: Row 2, column .05 gives 5.99. A χ2\chi^2 above 5.99 gives a p-value below 0.05.

Learn it: 3.15 Carrying Out a Chi-Square Test for Homogeneity or Independence

Not on the sheet: know these

The exam expects you to know these without being given them.