Skip to main content

Unit 9 · Topic 9.1

9.1 Kinetic Theory of Temperature and Pressure

Kinetic theory explains what a gas is doing at the atomic level. Pressure is the push of countless atoms bouncing off a surface, and temperature measures the average kinetic energy of those atoms. This topic links things you can measure with a gauge and a thermometer to the motion of particles you can't see.

Key terms

  • pressure
  • kinetic theory
  • average kinetic energy
  • Boltzmann constant
  • root-mean-square speed
  • Maxwell–Boltzmann distribution

What's changed recently

AP Physics 2 was revised for the 2024–25 school year. Its units are now numbered 9 to 15, picking up where AP Physics 1's Units 1–8 leave off, so thermodynamics is Unit 9 and this topic is 9.1. Older books and reviews number the course's units 1 to 7, with fluids as Unit 1 and thermodynamics as Unit 2.

Fluids (pressure in liquids, buoyancy and Bernoulli's equation) moved to AP Physics 1, so if an older Physics 2 review opens with fluids, you can skip that part. Going the other way, electric charge, simple circuits, and waves and sound left AP Physics 1, so this course now teaches them from the start (Units 10, 11 and 14).

The free-response questions changed in May 2025 to four set types: mathematical routines, translation between representations, experimental design and analysis, and qualitative/quantitative translation. Physics 2 free-response questions from 2024 and earlier are built differently.

Starting in May 2027, the multiple-choice section has 42 questions in 85 minutes (up from 40 in 80), and the four free-response questions take 95 minutes (down from 100). You can use a calculator and the equation sheet on both sections.

Where gas pressure comes from

A gas is a huge number of atoms flying around in random directions. When an atom hits a wall and bounces back, its momentum changes, so the wall must have pushed on it. By Newton's third law, the atom pushed back on the wall just as hard. One collision is a tiny tap, but trillions of them every second add up to a steady force.

Pressure is that force spread over an area: P=F⊥AP = \dfrac{F_\perp}{A}. Only the part of each push that is perpendicular to the surface counts. The unit is the pascal (1 Pa = 1 N/m²), and normal air pressure is about 1.0 × 10⁵ Pa, or 1 atmosphere.

Pressure isn't only at the walls. It exists everywhere inside the gas. If you placed a tiny surface anywhere in the middle of the container, atoms would hit both sides of it.

Collisions follow momentum rules

Atoms in an ideal gas collide elastically, with each other and with the walls. Momentum is conserved in atom–atom collisions, in one or two dimensions, just like the carts and pucks you studied in Physics 1.

For an atom of mass m that hits a wall head-on at speed v and bounces straight back, the change in momentum is 2mv (from +mv to −mv). A glancing hit changes only the perpendicular component of velocity, so it delivers less push.

Pressure goes up when collisions happen more often (more atoms, or a smaller container) or hit harder (faster atoms). Heating a gas does both at once.

Temperature is average kinetic energy

The temperature of a gas tells you the average translational kinetic energy of its atoms:

Kavg=32kBTK_{\text{avg}} = \frac{3}{2}k_BT

Here kB=1.38×10−23k_B = 1.38 \times 10^{-23} J/K is Boltzmann's constant and T must be in kelvins (K = °C + 273). Two big consequences follow. First, average kinetic energy is proportional to absolute temperature: double T in kelvins and you double KavgK_{\text{avg}}. Second, it doesn't depend on which gas it is. Helium and argon at the same temperature have the same average kinetic energy per atom.

Setting 12mvrms2=32kBT\frac{1}{2}mv_{\text{rms}}^2 = \frac{3}{2}k_BT gives the root-mean-square (rms) speed, vrms=3kBTmv_{\text{rms}} = \sqrt{\dfrac{3k_BT}{m}}. The rms speed is the square root of the average of the squared speeds. It's a typical speed, not the speed of every atom. Because m is in the denominator, lighter atoms move faster at the same temperature.

The Maxwell–Boltzmann distribution

Atoms in a gas don't all share one speed. Collisions constantly speed some up and slow others down. The Maxwell–Boltzmann distribution is a graph of how many atoms have each speed. It starts at zero (almost no atoms are nearly still), rises to a peak at the most probable speed, then falls off with a long tail toward high speeds. The curve is lopsided, with the tail stretching out to the right.

You need to know how its shape changes, not its formula.

  • Hotter gas: the peak moves to a higher speed and gets lower, and the curve spreads out. More atoms are very fast.
  • Same gas, same number of atoms: the area under the curve stays the same, because the area stands for the total number of atoms.
  • Heavier atoms at the same temperature: the peak sits at a lower speed and the curve is taller and narrower.

Worked examples

Try each one yourself first, then open the solution.

  1. Example 1Calculator allowed

    rms speed of helium

    Helium atoms have a mass of 6.64 × 10⁻²⁷ kg. Find the average kinetic energy and the rms speed of the atoms in helium gas at 300 K.

    Show the solution
    1. Step 1: Average kinetic energy: Kavg=32kBT=32(1.38×10−23)(300)=6.21×10−21K_{\text{avg}} = \frac{3}{2}k_BT = \frac{3}{2}(1.38 \times 10^{-23})(300) = 6.21 \times 10^{-21} J.
    2. Step 2: Solve 12mvrms2=Kavg\frac{1}{2}mv_{\text{rms}}^2 = K_{\text{avg}} for the speed: vrms=2Kavgm=2(6.21×10−21)6.64×10−27v_{\text{rms}} = \sqrt{\dfrac{2K_{\text{avg}}}{m}} = \sqrt{\dfrac{2(6.21 \times 10^{-21})}{6.64 \times 10^{-27}}}.
    3. Step 3: That gives about 1370 m/s, roughly four times the speed of sound in air.

    Answer: KavgK_{\text{avg}} ≈ 6.2 × 10⁻²¹ J and vrmsv_{\text{rms}} ≈ 1.4 × 10³ m/s

  2. Example 2Calculator allowed

    Doubling the temperature (classic trap)

    A gas is heated from 20 °C to 40 °C. A student says the average kinetic energy of its atoms doubles. Is that right? To what Celsius temperature would you have to heat the gas to really double its average kinetic energy?

    Show the solution
    1. Step 1: KavgK_{\text{avg}} is proportional to absolute temperature, so convert to kelvins: 20 °C = 293 K and 40 °C = 313 K.
    2. Step 2: The ratio is 313/293 ≈ 1.07, so the average kinetic energy rises by only about 7%. The student is wrong.
    3. Step 3: To double KavgK_{\text{avg}}, double the kelvin temperature: 2 × 293 K = 586 K, which is 586 − 273 = 313 °C.
    4. Step 4: Bonus: the rms speed goes as √T, so even at 586 K it rises only by a factor of √2 ≈ 1.41.

    Answer: No; it rises about 7%. Doubling KavgK_{\text{avg}} needs about 586 K, or 313 °C.

  3. Example 3Calculator allowed

    Pressure from many collisions

    In a simplified model, atoms of mass 6.6 × 10⁻²⁷ kg each hit a 0.010 m² wall head-on at 1200 m/s and bounce straight back. If 1.0 × 10²⁴ atoms hit the wall each second, what average pressure do they exert?

    Show the solution
    1. Step 1: Momentum change of one atom: from +mv to −mv, so ∣Δp∣=2mv=2(6.6×10−27)(1200)=1.58×10−23\lvert \Delta p \rvert = 2mv = 2(6.6 \times 10^{-27})(1200) = 1.58 \times 10^{-23} kg·m/s.
    2. Step 2: Average force = momentum delivered per second = (1.58 × 10⁻²³)(1.0 × 10²⁴) ≈ 15.8 N.
    3. Step 3: Pressure = F/A = 15.8 N / 0.010 m² ≈ 1.6 × 10³ Pa.

    Answer: About 1.6 × 10³ Pa

Common mistakes

  • Using Celsius in KavgK_{\text{avg}} = 32kBT\frac{3}{2}k_BT or in any ratio. Always convert to kelvins first.
  • Thinking heavier atoms have more kinetic energy at the same temperature. Same temperature means same average kinetic energy; heavier atoms just move slower.
  • Treating vrmsv_{\text{rms}} as the speed of every atom. Atoms have a spread of speeds given by the Maxwell–Boltzmann distribution.
  • Drawing a hotter Maxwell–Boltzmann curve taller. For the same number of atoms it gets lower and wider, keeping the same area.

On the exam

  • Expect to sketch or compare Maxwell–Boltzmann curves for two temperatures, or for two gases at the same temperature, and justify the shapes.
  • Factor-of-change questions are common: if T in kelvins goes up by 4, KavgK_{\text{avg}} goes up by 4 and vrmsv_{\text{rms}} by 2.
  • When explaining pressure, earn credit by naming the collisions, the momentum change at the wall, and the link between force and the rate of collisions.

Connected topics

Videos

  • AP Physics 2 - Unit 9 - Lesson 1 - Kinetic Theory of Gas

    Allen Tsao The STEM CoachWatch on YouTube (opens in a new tab)

  • Kinetic Theory and Temperature

    Bozeman ScienceWatch on YouTube (opens in a new tab)

  • Kinetic molecular theory of gases | Physics | Khan Academy

    Khan Academy PhysicsWatch on YouTube (opens in a new tab)

  • Kinetic Theory of Temperature and Pressure | AP Physics 2

    The Physics UniverseWatch on YouTube (opens in a new tab)

  • AP Physics 2 - Temperature

    Dan Fullerton (APlusPhysics)Watch on YouTube (opens in a new tab)

Check yourself

4 questions on 9.1 Kinetic Theory of Temperature and Pressure. Pick an answer to see if you got it, and why.

Question 1 of 4Calculator allowed

A sample of helium gas is at 300 K. What is the average kinetic energy of a helium atom in the sample?

Question 2 of 4Calculator allowed

The absolute temperature of an ideal gas is doubled. By what factor does the root-mean-square speed of its atoms change?

Question 3 of 4Calculator allowed

A container holds a mixture of helium atoms (mass 4 u) and argon atoms (mass 40 u) in thermal equilibrium. Which statement correctly compares the two kinds of atoms?

Question 4 of 4Calculator allowed

What is the root-mean-square speed of helium atoms (mass 6.64×10−276.64 \times 10^{-27} kg each) in a gas at 300 K?

0 of 4 answered