Short free-response question
Reading a photoelectron spectrum
- Unit 1
- 4 points
- About 9 minutes
You can use a calculator on this question, just like on exam day.
A shorter multipart question that sticks to one or two topics. Each part usually asks for one calculation, claim or explanation. On the exam: 4 questions (Questions 4–7), part of the 1-hour-45-minute free-response section; calculator allowed.
The question and its sources
The photoelectron spectrum (PES) of a gaseous sample of an element has four peaks. The table gives the binding energy of each peak and its relative height (proportional to the number of electrons).
Table 1. PES peaks of an unknown element
| Peak | Binding energy (MJ/mol) | Relative number of electrons |
|---|---|---|
| A | 104 | 2 |
| B | 6.84 | 2 |
| C | 3.67 | 6 |
| D | 0.50 | 1 |
Source: Standard values, rounded
Suggested time: 9 minutes
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Part (a)
1 pointIdentify the element, and write its complete ground-state electron configuration.
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Part (b)
1 pointThe binding energy of peak A is much greater than the binding energy of peak D. Explain this difference using Coulomb's law.
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Part (c)
1 pointDescribe how the peak for the 3s electrons in the PES of magnesium would compare with peak D, in terms of both its binding energy and its relative height. Justify your answer about binding energy.
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Part (d)
1 pointDescribe how the PES of the Na⁺ ion would differ from the spectrum in Table 1.
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