Short free-response question
Nitrosyl chloride: a small equilibrium constant
- Unit 7
- 4 points
- About 9 minutes
You can use a calculator on this question, just like on exam day.
A shorter multipart question that sticks to one or two topics. Each part usually asks for one calculation, claim or explanation. On the exam: 4 questions (Questions 4–7), part of the 1-hour-45-minute free-response section; calculator allowed.
The question
Nitrosyl chloride decomposes reversibly: 2 NOCl(g) ⇌ 2 NO(g) + Cl₂(g). At a certain temperature, Kc = 1.6 × 10⁻⁵.
Suggested time: 9 minutes
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Part (a)
1 pointCalculate the value of Kc for the reaction 4 NO(g) + 2 Cl₂(g) ⇌ 4 NOCl(g) at the same temperature.
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Part (b)
1 pointAt the same temperature, 2 NO(g) + O₂(g) ⇌ 2 NO₂(g) has Kc = 4.0 × 10³ (a hypothetical value for this question). Calculate Kc for the reaction 2 NOCl(g) + O₂(g) ⇌ 2 NO₂(g) + Cl₂(g).
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Part (c)
1 pointA sample of NOCl(g) with an initial concentration of 0.50 M is placed in an otherwise empty, rigid container and allowed to reach equilibrium at the same temperature. Calculate [Cl₂] at equilibrium.
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Part (d)
1 pointJustify the approximation that [NOCl] at equilibrium is essentially equal to 0.50 M, using both the magnitude of Kc and your answer to part (c).
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