Skip to main content

Unit 5 · Topic 5.1

5.1 Rotational Kinematics

Rotational kinematics describes how an object spins using angular position, angular velocity and angular acceleration. These follow exactly the same calculus rules as x, v and a from Unit 1, so derivatives, integrals, graph slopes and areas all carry over.

Key terms

  • angular position
  • angular displacement
  • angular velocity
  • angular acceleration
  • radian
  • rotational kinematic equations

What changed in the 2024 update

Before the Fall 2024 course update, this topic was part of one big Rotation unit (old Unit 5). That unit is now split in two: Unit 5 covers spinning motion, torque and rotational inertia, and Unit 6 covers rotational energy, angular momentum and rolling. Older videos and practice labeled "Unit 5: Rotation" still fit, but they may mix in Unit 6 ideas.

Measuring rotation in radians

Angular position θ tells you how far an object has turned from a reference line. In physics you measure it in radians. One radian is the angle where the arc length equals the radius, so θ=sr\theta = \dfrac{s}{r}. A full turn is 2π rad, which is 360°.

Angular displacement Δθ is the change in angular position. One direction of turning (usually counterclockwise) is called positive and the other negative. The problem may pick for you; if not, pick one and stick with it.

A rigid system is an object that keeps its shape while it turns, like a wheel or a door. Different points on it move in different directions at the same moment, so you can't treat it as a single point. If the spin doesn't matter for the question, you can still model it as one object. For example, you can ignore Earth's daily spin when you study its yearly orbit around the Sun.

Angular velocity and angular acceleration

Angular velocity is how fast the angular position changes: ω=dθdt\omega = \dfrac{d\theta}{dt}, in rad/s. Angular acceleration is how fast the angular velocity changes: α=dωdt\alpha = \dfrac{d\omega}{dt}, in rad/s².

Signs work just like in one-dimensional motion. If ω and α have the same sign, the object is spinning faster. If they have opposite signs, it's slowing down. When ω passes through zero, the object stops for an instant and reverses its direction of spin.

Problems often give speeds in revolutions per minute (rpm). Convert before you use any formula: multiply by 2π rad per revolution and divide by 60 s per minute.

Graphs and calculus

Everything you learned about x, v and a graphs works here with θ, ω and α. The slope of a θ–t graph is ω, and the slope of an ω–t graph is α. The area under an ω–t graph is Δθ, and the area under an α–t graph is Δω.

When α changes with time, integrate: ω(t)=ω0+∫0tα dt\omega(t) = \omega_0 + \displaystyle\int_0^t \alpha\,dt and θ(t)=θ0+∫0tω dt\theta(t) = \theta_0 + \displaystyle\int_0^t \omega\,dt. Don't forget the starting values ω₀ and θ₀.

Constant angular acceleration

When α is constant, you can use the rotational versions of the Unit 1 kinematic equations. Each one is the linear equation with x, v and a swapped for θ, ω and α:

ω=ω0+αtθ=θ0+ω0t+12αt2ω2=ω02+2α(θ−θ0)\omega = \omega_0 + \alpha t \qquad \theta = \theta_0 + \omega_0 t + \tfrac{1}{2}\alpha t^2 \qquad \omega^2 = \omega_0^2 + 2\alpha(\theta - \theta_0)

These only work for constant α. If α depends on time, go back to integrals.

LinearRotationalUnit
position xangular position θrad
velocity vangular velocity ωrad/s
acceleration aangular acceleration αrad/s²

What you won't be tested on

As vectors, ω and α point along the axis of rotation, set by a right-hand rule. The exam won't ask for those directions. You'll only describe rotation as clockwise or counterclockwise about a given axis, and you'll work with the signed sizes of θ, ω and α.

Worked examples

Try each one yourself first, then open the solution.

  1. Example 1Calculator allowed

    Constant angular acceleration

    A grinding wheel spins at 2.0 rad/s. It then speeds up with a constant angular acceleration of 1.5 rad/s² for 4.0 s. Find its final angular velocity and how many revolutions it makes during the 4.0 s.

    Show the solution
    1. Step 1: α is constant, so the kinematic equations apply. Final angular velocity: ω=ω0+αt=2.0+(1.5)(4.0)=8.0\omega = \omega_0 + \alpha t = 2.0 + (1.5)(4.0) = 8.0 rad/s.
    2. Step 2: Angular displacement: Δθ=ω0t+12αt2=(2.0)(4.0)+12(1.5)(4.0)2=8.0+12=20\Delta\theta = \omega_0 t + \tfrac{1}{2}\alpha t^2 = (2.0)(4.0) + \tfrac{1}{2}(1.5)(4.0)^2 = 8.0 + 12 = 20 rad.
    3. Step 3: Convert to revolutions: 20 rad2π rad/rev≈3.2\dfrac{20\text{ rad}}{2\pi\text{ rad/rev}} \approx 3.2 rev.

    Answer: ω = 8.0 rad/s; Δθ = 20 rad, about 3.2 revolutions

  2. Example 2

    Derivatives from an angle function

    A turntable's angular position is θ(t)=2t3−6t\theta(t) = 2t^3 - 6t, with θ in radians and t in seconds, for t ≥ 0. When is the turntable momentarily at rest, and what is its angular acceleration at t = 2.0 s?

    Show the solution
    1. Step 1: Differentiate once for angular velocity: ω=dθdt=6t2−6\omega = \dfrac{d\theta}{dt} = 6t^2 - 6.
    2. Step 2: Set ω = 0: 6t2=66t^2 = 6, so t = 1.0 s (the root t = −1 s is outside the time range). Before t = 1.0 s, ω is negative; after, it's positive, so the spin reverses there.
    3. Step 3: Differentiate again: α=dωdt=12t\alpha = \dfrac{d\omega}{dt} = 12t. At t = 2.0 s, α = 24 rad/s².

    Answer: At rest at t = 1.0 s; α = 24 rad/s² at t = 2.0 s

  3. Example 3

    Changing α (classic trap)

    A motor gives a fan blade an angular acceleration α(t) = 4t rad/s², with t in seconds. At t = 0 the blade spins at 3.0 rad/s. Find ω at t = 2.0 s and the angle the blade turns through from t = 0 to t = 2.0 s.

    Show the solution
    1. Step 1: The trap is using ω=ω0+αt\omega = \omega_0 + \alpha t with α(2) = 8 rad/s², which gives 19 rad/s. That's wrong, because α isn't constant.
    2. Step 2: Integrate instead: ω(t)=3.0+∫0t4t dt=3.0+2t2\omega(t) = 3.0 + \displaystyle\int_0^t 4t\,dt = 3.0 + 2t^2. At t = 2.0 s, ω = 3.0 + 8.0 = 11 rad/s.
    3. Step 3: Integrate again for the angle: Δθ=∫02(3+2t2) dt=6+163≈11.3\Delta\theta = \displaystyle\int_0^{2} (3 + 2t^2)\,dt = 6 + \dfrac{16}{3} \approx 11.3 rad.

    Answer: ω = 11 rad/s; Δθ ≈ 11.3 rad

Common mistakes

  • Plugging rpm or degrees into rotational formulas. Convert to rad/s and radians first.
  • Using the constant-α equations when α changes with time. If α is a function of t, integrate.
  • Deciding an object is slowing down because α is negative. It's slowing down only when ω and α have opposite signs.
  • Forgetting the initial value ω₀ or θ₀ after integrating.

On the exam

  • Expect to sketch or read θ–t, ω–t and α–t graphs. Use slopes and areas exactly as you did for x, v and a.
  • Free-response questions often give θ(t) or α(t) as a function. Show the derivative or integral you used, with limits, before plugging in numbers.

Connected topics

Videos

  • Topic 5.1 - Rotational Kinematics

    Lessons With LondotWatch on YouTube (opens in a new tab)

  • Complete Rotational Kinematics Concepts in just 12 minutes ⌛ | AP Physics 1 - Unit 5 Lesson 2

    Allen Tsao The STEM CoachWatch on YouTube (opens in a new tab)

  • AP Physics C: Rotational Kinematics Review (Mechanics)

    Flipping PhysicsWatch on YouTube (opens in a new tab)

  • AP Physics C - Rotational Kinematics

    Dan Fullerton (APlusPhysics)Watch on YouTube (opens in a new tab)

  • 10.3 Worked Example - Angular position from angular acceleration.

    MIT OpenCourseWareWatch on YouTube (opens in a new tab)

  • Rotational Kinematics Physics Problems, Basic Introduction, Equations & Formulas

    The Organic Chemistry TutorWatch on YouTube (opens in a new tab)

Check yourself

4 questions on 5.1 Rotational Kinematics. Pick an answer to see if you got it, and why.

Question 1 of 4Calculator allowed

A wheel's angular position is θ(t)=2t3−3t2\theta(t) = 2t^3 - 3t^2, with θ in radians and t in seconds. What is the wheel's angular velocity at t = 2 s?

Question 2 of 4Calculator allowed

A grinding wheel starts from rest and has a constant angular acceleration of 4.0 rad/s² for 5.0 s. About how many revolutions does it make in that time?

Question 3 of 4Calculator allowed

A ceiling fan spinning at 30 rad/s slows down with constant angular acceleration and stops in 6.0 s. Through what angle does it turn while stopping?

Question 4 of 4Calculator allowed

A rotor starts from rest at θ = 0 at t = 0. Its angular acceleration is α(t)=6t\alpha(t) = 6t, in rad/s² with t in seconds. What is its angular position at t = 2.0 s?

0 of 4 answered