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Unit 8 · Topic 8.1

8.1 Electric Charge and Electric Force

Electric charge is the property that makes objects push or pull on each other electrically, and it comes in whole-number multiples of the elementary charge e. Coulomb's law tells you the size and direction of the force between two point charges, and every other force calculation in this unit is built from it.

Key terms

  • elementary charge (e)
  • point charge
  • Coulomb’s law
  • electrostatic force
  • permittivity of free space
  • conductor and insulator

Charge and its smallest piece

Charge is measured in coulombs (C). It comes in two kinds, positive and negative. A proton carries +e, an electron carries −e and a neutron has no charge, where e = 1.60 × 10⁻¹⁹ C is the elementary charge: the size of the charge on one proton or one electron.

Any object's net charge is a whole-number multiple of e, because it's made of a whole number of extra or missing electrons. We say charge is quantized. One coulomb is a huge amount, so real problems use microcoulombs (1 μC = 10⁻⁶ C) and nanocoulombs (1 nC = 10⁻⁹ C).

A point charge is a charged object small enough, compared with the distances in the problem, that you can treat all its charge as sitting at one point.

Coulomb's law

The force between two point charges has magnitude FE=14πε0∣q1q2∣r2=k∣q1q2∣r2F_E = \frac{1}{4\pi\varepsilon_0}\frac{\lvert q_1 q_2 \rvert}{r^2} = k\frac{\lvert q_1 q_2 \rvert}{r^2}

Here r is the distance between the charges and k ≈ 9.0 × 10⁹ N·m²/C². The constant ε₀ = 8.85 × 10⁻¹² C²/(N·m²) is the permittivity of free space. Think of it as the number that sets how strongly charges interact across empty space. Both constants are on the equation sheet, and you'll use whichever one makes later formulas tidier.

The force acts along the line joining the charges. Like charges repel and opposite charges attract. By Newton's third law, the two charges feel forces of equal size in opposite directions, even if one charge is much bigger than the other.

ChangeEffect on F
double one chargeF doubles
double both chargesF is 4 times as large
double the distanceF drops to ¼
halve the distanceF is 4 times as large

Adding forces from several charges

When several charges act on one charge, each pair interacts as if the others weren't there. The net force is the vector sum of the separate Coulomb forces. This is called superposition.

The method: find the magnitude of each force with Coulomb's law (use magnitudes of the charges), decide each direction from attract or repel, break each force into x- and y-components, then add the components. The exam keeps these to four or fewer charges, unless a symmetric arrangement makes most of the work cancel.

Electric force versus gravity

Both forces fall off as 1/r², but they differ in two ways. Gravity only ever attracts, while the electric force can attract or repel. And the electric force is far stronger. For two protons, the electric repulsion is about 10³⁶ times their gravitational attraction. That's why you can ignore gravity for electrons, protons and ions in electric problems unless the question says otherwise.

Gravity still wins for planets and people, because large objects are almost perfectly neutral: their positive and negative charges cancel, while mass only adds up.

Electric forces also hide inside many everyday forces. The normal force, friction and tension all come from electric pushes and pulls between the atoms of surfaces in contact. There are far too many atoms to track one by one, so you treat these as contact forces instead.

Conductors and insulators

In a conductor, such as a metal, some electrons are free to move through the whole material. Extra charge placed on a conductor spreads out quickly. In an insulator, such as glass, rubber or plastic, electrons are bound to their atoms, so extra charge mostly stays where you put it. This difference explains how objects get charged (8.2) and how conductors behave in fields (10.1).

Materials also differ in permittivity: how easily a field can polarize them, meaning how far it can shift their electrons to one side. Empty space has the fixed value ε₀. Any material's permittivity is different, because it depends on how its atoms and electrons are arranged and how freely those electrons can rearrange. You'll use this idea with dielectrics in capacitors (10.4).

Worked examples

Try each one yourself first, then open the solution.

  1. Example 1Calculator allowed

    Force between two point charges

    A +3.0 μC charge and a −5.0 μC charge are 0.20 m apart. Find the magnitude and direction of the force each exerts on the other.

    Show the solution
    1. Step 1: Use magnitudes in Coulomb's law: F=(9.0×109)(3.0×10−6)(5.0×10−6)(0.20)2F = \dfrac{(9.0\times10^{9})(3.0\times10^{-6})(5.0\times10^{-6})}{(0.20)^2}.
    2. Step 2: The numerator is 0.135 and the denominator is 0.040, so F ≈ 3.4 N.
    3. Step 3: The charges have opposite signs, so the force is attractive. Each charge is pulled toward the other with the same 3.4 N.

    Answer: About 3.4 N on each charge, attractive (each pulled toward the other)

  2. Example 2Calculator allowed

    Net force from two charges at right angles

    Charge q₁ = +2.0 μC sits at the origin. Charge q₂ = +2.0 μC is at x = 0.30 m on the x-axis, and q₃ = −1.0 μC is at y = 0.40 m on the y-axis. Find the net electric force on q₁.

    Show the solution
    1. Step 1: Force from q₂: F12=(9.0×109)(2.0×10−6)(2.0×10−6)(0.30)2=0.40F_{12} = \dfrac{(9.0\times10^{9})(2.0\times10^{-6})(2.0\times10^{-6})}{(0.30)^2} = 0.40 N. Both charges are positive, so q₁ is pushed away from q₂, in the −x direction.
    2. Step 2: Force from q₃: F13=(9.0×109)(2.0×10−6)(1.0×10−6)(0.40)2≈0.113F_{13} = \dfrac{(9.0\times10^{9})(2.0\times10^{-6})(1.0\times10^{-6})}{(0.40)^2} \approx 0.113 N. Opposite signs attract, so q₁ is pulled toward q₃, in the +y direction.
    3. Step 3: Components: Fx=−0.40F_x = -0.40 N and Fy=+0.113F_y = +0.113 N. Magnitude: 0.402+0.1132≈0.42\sqrt{0.40^2 + 0.113^2} \approx 0.42 N.
    4. Step 4: Direction: tan⁡−1(0.113/0.40)≈16∘\tan^{-1}(0.113/0.40) \approx 16^\circ above the −x axis.

    Answer: About 0.42 N, pointing 16° above the −x direction

  3. Example 3Calculator allowed

    Electric force vs. gravity (classic trap)

    Two protons (each m = 1.67 × 10⁻²⁷ kg) are some distance r apart. How many times larger is the electric force than the gravitational force? Does your answer depend on r?

    Show the solution
    1. Step 1: Both forces go as 1/r², so the ratio doesn't depend on r: FEFG=ke2Gm2\dfrac{F_E}{F_G} = \dfrac{k e^2}{G m^2}.
    2. Step 2: Substitute: (9.0×109)(1.60×10−19)2(6.67×10−11)(1.67×10−27)2≈1.2×1036\dfrac{(9.0\times10^{9})(1.60\times10^{-19})^2}{(6.67\times10^{-11})(1.67\times10^{-27})^2} \approx 1.2\times10^{36}.
    3. Step 3: The trap is thinking that a tiny charge makes a tiny force that must compete with gravity. For particles, gravity is negligible.

    Answer: About 1.2 × 10³⁶ times larger, at any separation

Common mistakes

  • Plugging signed charges into Coulomb's law and then reading the sign as a direction. Use magnitudes for the size, then find the direction from like-repels, opposites-attract.
  • Using the distance from one charge to the origin instead of the distance between the two charges.
  • Adding force magnitudes from several charges as plain numbers. Forces are vectors: add components.
  • Thinking the larger charge feels the larger force. The two forces in a pair are always equal in size and opposite in direction.

On the exam

  • Expect ratio questions: if one charge triples and the distance doubles, the force becomes 3/4 as large. Multiply the factors instead of recomputing.
  • Free-response answers are often symbolic. Write forces in terms of the given letters, such as kQ2d2\dfrac{kQ^2}{d^2} or Q24πε0d2\dfrac{Q^2}{4\pi\varepsilon_0 d^2}, and draw a clear force diagram with each arrow labeled.

Connected topics

Videos

  • AP Physics C E&M - Unit 8 - Lesson 1 - Electric Force

    Allen Tsao The STEM CoachWatch on YouTube (opens in a new tab)

  • Topic 8.1 - Electric Charge and Electric Force

    Lessons With LondotWatch on YouTube (opens in a new tab)

  • Electric charge and electric force | AP Physics | Khan Academy

    Khan AcademyWatch on YouTube (opens in a new tab)

  • Introduction to Coulomb's Law or the Electric Force

    Flipping PhysicsWatch on YouTube (opens in a new tab)

  • Electric Charge: Crash Course Physics #25

    CrashCourseWatch on YouTube (opens in a new tab)

  • AP Physics C - Charges and Coulomb's Law

    Dan Fullerton (APlusPhysics)Watch on YouTube (opens in a new tab)

Check yourself

4 questions on 8.1 Electric Charge and Electric Force. Pick an answer to see if you got it, and why.

Question 1 of 4Calculator allowed

A +3.0 μC point charge and a −5.0 μC point charge are 0.30 m apart. What are the magnitude and nature of the electric force between them?

Question 2 of 4Calculator allowed

Two point charges a distance r apart exert a force of magnitude F on each other. Both charges are doubled and the distance between them is tripled. What is the new magnitude of the force?

Question 3 of 4Calculator allowed

Three point charges lie on the x-axis: +2.0 μC at x = 0, +1.0 μC at x = 0.10 m and −3.0 μC at x = 0.30 m. What is the net electric force on the +1.0 μC charge?

Question 4 of 4Calculator allowed

Two protons are a distance r apart. Roughly what is the ratio of the electric force between them to the gravitational force between them? (Proton mass 1.67×10−271.67 \times 10^{-27} kg, G=6.67×10−11G = 6.67 \times 10^{-11} N·m²/kg².)

0 of 4 answered