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Unit 15 · Topic 15.7

15.7 Fission, Fusion, and Nuclear Decay

Updated for 2026–27: College Board now states plainly that a nucleus dropping to a lower energy level without becoming a different nucleus (gamma decay) counts as radioactive decay. The strong force binds protons and neutrons in the nucleus. Every nuclear reaction conserves nucleon number, charge, energy and momentum, and any mass that disappears becomes energy by E = mc². Fusion joins light nuclei and fission splits heavy ones, and both can release energy. Radioactive decay is random for a single nucleus, but a large sample follows a predictable half-life.

Key terms

  • strong force
  • mass-energy equivalence
  • nuclear fusion
  • nuclear fission
  • half-life
  • decay constant

The strong force

Protons in a nucleus repel each other strongly, yet nuclei hold together. The strong force, an attraction between nucleons (protons and neutrons), is much stronger than the electric force at nuclear distances but has a very short range, only a few nucleon widths (a few times 10⁻¹⁵ m). That's why it dominates inside the nucleus and is negligible outside it.

Conservation laws in nuclear reactions

  • Nucleon number: the total of protons plus neutrons (the top numbers, A) is the same before and after.
  • Charge: the total charge (the bottom numbers, Z, for nuclei) is the same before and after.
  • Energy, counting mass as a form of energy.
  • Momentum: the products' momenta add up to the starting momentum, so a nucleus at rest that splits sends its pieces off in opposite directions.

Mass-energy equivalence

Einstein's E = mc² says mass and energy are interchangeable. In a nuclear reaction, the total mass of the products is often slightly less than the total mass of the reactants. That missing mass Δm has turned into energy, E=(Δm)c2E = (\Delta m)c^2, which appears as kinetic energy of the products or as gamma-ray photons.

Nuclear masses are given in unified atomic mass units (u). The equation sheet gives 1 u = 1.66 × 10⁻²⁷ kg = 931 MeV/c², so each 1 u of missing mass releases 931 MeV.

Because c² is enormous, a tiny mass change releases a huge energy. Nuclear reactions release millions of times more energy per atom than chemical reactions.

Fusion and fission

Fusion joins two or more light nuclei into a heavier one, often with a neutron or other particle given off. The Sun runs on fusion of hydrogen into helium. It needs huge temperatures so the positive nuclei move fast enough to get close despite their repulsion.

Fission splits a heavy nucleus into two or more lighter nuclei plus a few neutrons. Some heavy nuclei split spontaneously; others need an energy input, such as absorbing a neutron, as uranium-235 does in a nuclear reactor. The freed neutrons can trigger more fissions.

Both release energy for the same reason: the products are more tightly bound than the reactants, so they have less total mass.

Radioactive decay and half-life

In radioactive decay, an unstable nucleus changes on its own. Either it turns into a different nucleus (or several), or it settles from an excited state into a lower-energy state of the same nucleus, as in gamma decay (15.8). College Board spelled out that second case in its fall 2026 update to the course description, so if you're asked whether gamma decay counts as radioactive decay, the answer is yes. You can't predict when a particular nucleus will decay, any more than you can predict one coin flip. But a sample of billions of nuclei decays very predictably.

The half-life t1/2t_{1/2} is the time for half of the radioactive nuclei in a sample to decay. After one half-life ½ remain, after two ¼, after three ⅛, and so on. Some isotopes have half-lives far shorter than a second and others have half-lives of billions of years. You won't need to memorize any.

The decay constant λ (a different λ from wavelength) is related by λ=ln⁡2t1/2\lambda = \frac{\ln 2}{t_{1/2}}. The number left after time t is N=N0e−λtN = N_0 e^{-\lambda t}, which is the same as N=N0(12)t/t1/2N = N_0\left(\frac{1}{2}\right)^{t/t_{1/2}}.

A graph of N against t is a decreasing exponential curve. If you know how much was there at the start, you can use the fraction remaining to find a sample's age; that's how radiocarbon dating works.

Worked examples

Try each one yourself first, then open the solution.

  1. Example 1Calculator allowed

    Energy from fusion

    Deuterium (2.014102 u) fuses with tritium (3.016049 u) to make helium-4 (4.002603 u) and a neutron (1.008665 u). How much energy is released?

    Show the solution
    1. Step 1: Mass before: 2.014102 + 3.016049 = 5.030151 u. Mass after: 4.002603 + 1.008665 = 5.011268 u.
    2. Step 2: Missing mass: Δm = 5.030151 − 5.011268 = 0.018883 u.
    3. Step 3: Energy: (0.018883 u)(931 MeV/u) = 17.6 MeV, carried off mostly as kinetic energy of the neutron and the helium nucleus.

    Answer: About 17.6 MeV

  2. Example 2

    Balancing a fission reaction

    A uranium-235 nucleus absorbs a neutron and splits: 01n+92235U→54140Xe+3894Sr+x 01n{}^{1}_{0}\text{n} + {}^{235}_{92}\text{U} \to {}^{140}_{54}\text{Xe} + {}^{94}_{38}\text{Sr} + x\,{}^{1}_{0}\text{n}. How many neutrons x are released?

    Show the solution
    1. Step 1: Charge check: 0 + 92 = 92 on the left; 54 + 38 = 92 on the right. Neutrons carry no charge, so charge balances for any x.
    2. Step 2: Nucleon number: 1 + 235 = 236 on the left. On the right, 140 + 94 + x = 234 + x.
    3. Step 3: Set them equal: 234 + x = 236, so x = 2.

    Answer: 2 neutrons

  3. Example 3Calculator allowed

    Half-life calculation

    A sample contains 8.0 g of an isotope with a half-life of 5.0 days. How much of the isotope remains after (a) 15 days and (b) 12 days? What is its decay constant?

    Show the solution
    1. Step 1: (a) 15 days is exactly 3 half-lives: 8.0 → 4.0 → 2.0 → 1.0 g.
    2. Step 2: (b) 12 days is 12/5.0 = 2.4 half-lives, not a whole number, so use the equation: N=(8.0 g)(12)2.4=1.5N = (8.0\text{ g})\left(\frac{1}{2}\right)^{2.4} = 1.5 g.
    3. Step 3: Decay constant: λ=ln⁡2t1/2=0.6935.0 days=0.139\lambda = \dfrac{\ln 2}{t_{1/2}} = \dfrac{0.693}{5.0\text{ days}} = 0.139 per day. Check: 8.0 e−(0.139)(12)=1.58.0\,e^{-(0.139)(12)} = 1.5 g.

    Answer: (a) 1.0 g, (b) 1.5 g; λ ≈ 0.139 per day

Common mistakes

  • Thinking that after two half-lives the sample is gone. Each half-life removes half of what's left: ¼ remains after two.
  • Forgetting to convert mass to energy with 931 MeV per u, or subtracting the masses in the wrong order. Energy is released when the products have less mass.
  • Assuming a single nucleus decays after exactly one half-life. Individual decays are random; the half-life only describes large samples.
  • Checking only nucleon number when balancing. Charge must balance too.

On the exam

  • Expect to balance reactions using nucleon number and charge, and to find energy released from a mass difference.
  • Graph questions may give decay data. Read the half-life as the time for N to halve, or linearize by graphing ln N against t, which gives a straight line with slope −λ.

Connected topics

Videos

  • AP Physics 2 - Unit 15 - Lesson 3 - Mass-Energy Equivalence

    Allen Tsao The STEM CoachWatch on YouTube (opens in a new tab)

  • Nuclear fission | Physics | Khan Academy

    Khan AcademyWatch on YouTube (opens in a new tab)

  • Nuclear Physics: Crash Course Physics #45

    CrashCourseWatch on YouTube (opens in a new tab)

  • AP Physics 2 - Unit 15 - Lesson 4 - Half Life

    Allen Tsao The STEM CoachWatch on YouTube (opens in a new tab)

  • Half-Life and Radioactive Decay

    Bozeman ScienceWatch on YouTube (opens in a new tab)

  • Nuclear Reactions, Radioactivity, Fission and Fusion

    Professor Dave ExplainsWatch on YouTube (opens in a new tab)

Check yourself

5 questions on 15.7 Fission, Fusion, and Nuclear Decay. Pick an answer to see if you got it, and why.

Question 1 of 5Calculator allowed

In a nuclear reaction, the total mass of the products is 0.0300 u less than the total mass of the reactants. How much energy is released? (1 u is equivalent to 931 MeV.)

Question 2 of 5Calculator allowed

If 1.0 g of matter were converted entirely into energy, how much energy would be released?

Question 3 of 5Calculator allowed

Uranium-235 absorbs a neutron and splits: 01n{}^{1}_{0}\text{n} + 92235U{}^{235}_{92}\text{U} → 56144Ba{}^{144}_{56}\text{Ba} + X + 301n{}^{1}_{0}\text{n}. What is X?

In a fusion reactor, deuterium and tritium nuclei fuse: 12H{}^{2}_{1}\text{H} + 13H{}^{3}_{1}\text{H} → 24He{}^{4}_{2}\text{He} + 01n{}^{1}_{0}\text{n}.

Masses: deuterium 2.014102 u, tritium 3.016049 u, helium-4 4.002603 u, neutron 1.008665 u. 1 u is equivalent to 931 MeV.

Described reaction

Question 4 of 5Calculator allowed

How much energy is released in one fusion reaction?

Question 5 of 5Calculator allowed

Where does most of this released energy show up right after the reaction?

0 of 5 answered