AP® Calculus BC review sheet from Aim for Five (aimforfive.com/calc-bc/units/9/9-7)
Unit 9 · Topic 9.7
BC only9.7 Defining Polar Coordinates and Differentiating in Polar Form
BC only. Polar coordinates locate a point by its distance r from the origin and its angle θ. To find slopes of a polar curve r = f(θ), write x = r cos θ and y = r sin θ, then use dy/dx = (dy/dθ)/(dx/dθ). The derivative dr/dθ is different: it tells you whether the curve is moving toward or away from the origin.
Key terms
- polar coordinates
- x = r cos θ, y = r sin θ
- dy/dx
- dr/dθ
- pole (origin)
Polar coordinates
This whole unit is BC only. A point in polar form is (r, θ): go out a distance r from the origin (called the pole) in the direction of the angle θ, measured from the positive x-axis. A negative r means go the opposite direction, so (−2, π/4) is the same point as (2, 5π/4).
Converting between forms:
- x = r cos θ and y = r sin θ
- r² = x² + y² and tan θ = y/x (for x ≠ 0)
- A polar curve r = f(θ) becomes the parametric curve x = f(θ) cos θ, y = f(θ) sin θ, with θ as the parameter.
Slope of a polar curve
Since a polar curve is a parametric curve in θ, use the 9.1 formula:
dy/dx = (dy/dθ)/(dx/dθ), where dx/dθ = r′ cos θ − r sin θ and dy/dθ = r′ sin θ + r cos θ, with r′ = dr/dθ.
Those come from the product rule on x = r cos θ and y = r sin θ. You don't need to memorize them; just differentiate. Horizontal tangents occur where dy/dθ = 0 and dx/dθ ≠ 0, and vertical tangents where dx/dθ = 0 and dy/dθ ≠ 0.
What dr/dθ tells you
dr/dθ is the rate at which the distance from the origin changes as θ increases. It is not the slope of the curve. Whether the curve moves toward or away from the origin depends on the signs of both r and dr/dθ:
| r | dr/dθ | The curve is… |
|---|---|---|
| positive | positive | moving away from the origin |
| positive | negative | moving toward the origin |
| negative | negative | moving away from the origin (the size of r is growing) |
| negative | positive | moving toward the origin (the size of r is shrinking) |
Rates of change of x and y
Read the question's wording carefully. “Distance from the origin” is about r, so use dr/dθ. “Distance from the x-axis” or “height” is about y, so use dy/dθ. dx/dθ and dy/dθ tell you how the x- and y-coordinates change as θ increases. A question might ask whether the curve is getting closer to the x-axis at some θ. That's about whether |y| is decreasing: look at the signs of y and dy/dθ together. Always compute these with y = r sin θ and x = r cos θ, not with r alone.
Worked examples
Try each one yourself first, then open the solution.
- Example 1
Slope of a cardioid
Find the slope of the curve r = 2 + 2 cos θ at θ = π/2, and give the point.
Show the solutionHide the solution
- Step 1: r(π/2) = 2 + 0 = 2. The point is x = 2 cos(π/2) = 0, y = 2 sin(π/2) = 2, so (0, 2).
- Step 2: r′ = −2 sin θ, so r′(π/2) = −2.
- Step 3: dx/dθ = r′ cos θ − r sin θ = (−2)(0) − (2)(1) = −2.
- Step 4: dy/dθ = r′ sin θ + r cos θ = (−2)(1) + (2)(0) = −2.
- Step 5: dy/dx = (−2)/(−2) = 1.
Answer: Slope 1 at the point (0, 2)
- Example 2
Trap: dr/dθ with negative r
For r = 1 + 2 cos θ, is the curve moving toward or away from the origin at θ = π/3? At θ = 3π/4? Also find dy/dθ at θ = π/2.
Show the solutionHide the solution
- Step 1: dr/dθ = −2 sin θ.
- Step 2: At θ = π/3: r = 1 + 2(½) = 2 > 0 and dr/dθ = −√3 < 0. r is positive and shrinking, so the curve moves toward the origin.
- Step 3: At θ = 3π/4: r = 1 + 2(−√2/2) = 1 − √2 ≈ −0.414 < 0 and dr/dθ = −2(√2/2) = −√2 < 0. r is negative and getting more negative, so |r| is growing: the curve moves away from the origin.
- Step 4: A student who only looks at dr/dθ < 0 would wrongly say “toward” both times.
- Step 5: For dy/dθ: y = r sin θ = sin θ + 2 sin θ cos θ = sin θ + sin 2θ, so dy/dθ = cos θ + 2 cos 2θ. At θ = π/2: 0 + 2(−1) = −2.
Answer: Toward the origin at θ = π/3; away from it at θ = 3π/4. dy/dθ = −2 at θ = π/2.
Common mistakes
- Using dr/dθ as the slope of the curve. The slope is dy/dx.
- Forgetting the product rule when differentiating r cos θ and r sin θ.
- Deciding toward/away from dr/dθ alone when r is negative.
- Working in degree mode on the calculator.
On the exam
- BC free-response polar questions often ask for the slope at a given θ, the meaning of dr/dθ in context, and an area (9.8, 9.9).
- When explaining dr/dθ, mention both r's sign and dr/dθ's sign: “Since r > 0 and dr/dθ < 0, the curve is getting closer to the origin.”
Connected topics
Videos
Check yourself
4 questions on 9.7 Defining Polar Coordinates and Differentiating in Polar Form. Pick an answer to see if you got it, and why.
What is the slope of the line tangent to the polar curve r = 1 + 2sin θ at the point where θ = π/6?
For the polar curve r = 1 + 2cos θ, which of the following is true at θ = 3π/4?
A particle moves along the polar curve r = 1 + θ sin θ. What is the rate of change of the particle's y-coordinate with respect to θ when θ = 2?
A point has polar coordinates (r, θ) = (−2, π/3). What are its rectangular coordinates (x, y)?
0 of 4 answered