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Unit 1 · Topic 1.14

1.14 Connecting Infinite Limits and Vertical Asymptotes

When a function's outputs grow without bound as x approaches c, you describe that with an infinite limit, written ∞ or −∞. The line x = c is then a vertical asymptote. The sign of the function on each side tells you whether the graph shoots up or down.

Key terms

  • infinite limit
  • unbounded
  • vertical asymptote
  • one-sided behavior

Infinite limits

lim (x→c⁺) f(x) = ∞ means the outputs become larger than any number you pick as x approaches c from the right. Similarly, −∞ means they become more and more negative.

An infinite limit is not a real number, so technically the limit does not exist. Writing ∞ or −∞ is more informative: it tells you how the limit fails. If the right side goes to ∞ and the left side to −∞, the two-sided limit doesn't exist even in that sense.

Vertical asymptotes

The line x = c is a vertical asymptote of f if at least one one-sided limit at c is ∞ or −∞. You only need one side.

Typical sources: a rational function whose denominator is 0 at c but whose top is not (after canceling); ln x at x = 0 (lim (x→0⁺) ln x = −∞); and tan x and sec x at odd multiples of π/2.

Finding the sign on each side

When substitution gives (nonzero number)/0, the quotient is unbounded. To find the sign, test a number just to the side. For example, use x = 3.01 to see the sign just right of 3.

Or reason with factors: decide whether each factor is positive or negative just to that side, then multiply the signs. A squared factor like (x − 2)² is positive on both sides, so both one-sided limits have the same sign.

Top near cBottom near cQuotient heads to
Positive0 through positive values∞
Positive0 through negative values−∞
Negative0 through positive values−∞
Negative0 through negative values∞

Working with infinite limits

∞ is not a number, so the usual limit properties don't apply directly. Some patterns are safe: if f(x)→∞ and g(x)→5, then f(x) + g(x)→∞ and f(x)·g(x)→∞ (since 5 > 0). Others are undecided: ∞ − ∞, 0·∞ and ∞/∞ can come out to anything, so you'd need to rewrite.

Graphs help too. Near a vertical asymptote, a curve that climbs on both sides, like 1/x² near 0, has lim (x→0) 1/x² = ∞ from both sides. A curve that climbs on one side and falls on the other, like 1/x near 0, has different one-sided infinite limits.

Worked examples

Try each one yourself first, then open the solution.

  1. Example 1

    Signs on both sides of two asymptotes

    Let f(x) = (x + 2) / (x² − 9). Find the one-sided limits at x = 3 and at x = −3.

    Show the solution
    1. Step 1: Write the bottom as (x − 3)(x + 3). At x = 3 the top is 5 and the bottom is 0, so both one-sided limits are infinite.
    2. Step 2: Just right of 3 (like 3.01): x − 3 > 0 and x + 3 > 0, so the bottom is a tiny positive number. 5 over tiny positive → ∞.
    3. Step 3: Just left of 3 (like 2.99): x − 3 < 0 and x + 3 > 0, so the bottom is tiny negative. 5 over tiny negative → −∞.
    4. Step 4: At x = −3 the top is −1. Just right of −3 (like −2.99): x − 3 < 0 and x + 3 > 0, so the bottom is tiny negative. −1 over tiny negative → ∞.
    5. Step 5: Just left of −3 (like −3.01): x − 3 < 0 and x + 3 < 0, so the bottom is tiny positive. −1 over tiny positive → −∞.

    Answer: lim (x→3⁺) f(x) = ∞, lim (x→3⁻) f(x) = −∞, lim (x→−3⁺) f(x) = ∞, lim (x→−3⁻) f(x) = −∞. Both x = 3 and x = −3 are vertical asymptotes.

  2. Example 2

    Trap: a zero denominator that is not an asymptote

    Does g(x) = (x² − 4) / (x − 2) have a vertical asymptote at x = 2?

    Show the solution
    1. Step 1: Substitution gives 0/0, not (nonzero)/0. That's the sign to factor.
    2. Step 2: (x² − 4) / (x − 2) = (x − 2)(x + 2) / (x − 2) = x + 2 for x ≠ 2.
    3. Step 3: lim (x→2) g(x) = 4, a finite number.

    Answer: No. g has a hole at (2, 4), not a vertical asymptote, because the limit at 2 is 4.

Common mistakes

  • Saying a function has a vertical asymptote wherever the denominator is 0, without checking whether the factor cancels.
  • Guessing the sign of an infinite limit. Test a value just to that side or track the sign of each factor.
  • Writing lim (x→3) f(x) = ∞ when the two sides go in opposite directions. Then you must write the one-sided limits separately.

On the exam

  • Multiple-choice questions ask for vertical asymptotes of a rational function or for the value of a one-sided infinite limit.
  • When a question asks you to justify a vertical asymptote, give a one-sided limit that equals ∞ or −∞.

Connected topics

Videos

  • Calculus AB/BC – 1.14 Infinite Limits and Vertical Asymptotes

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  • Infinite limits intro | Limits and continuity | AP Calculus AB | Khan Academy

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  • AP Calculus AB TOPIC 1.14 Connecting Infinite Limits and Vertical Asymptotes

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  • Calculus - How to find limits with infinity using the graph

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  • What is an infinite limit?

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  • Infinite limits and asymptotes | Limits and continuity | AP Calculus AB | Khan Academy

    Khan AcademyWatch on YouTube (opens in a new tab)

Check yourself

4 questions on 1.14 Connecting Infinite Limits and Vertical Asymptotes. Pick an answer to see if you got it, and why.

Question 1 of 4

What is lim (x→2⁻) (x + 1)/(x² − 4) ?

Question 2 of 4

What is lim (x→1⁺) (x − 3)/ln x ?

Question 3 of 4

When x = 1 is substituted into (x² + 3)/(x − 1), the result is 4/0. Which of the following is true about lim (x→1) (x² + 3)/(x − 1) ?

Question 4 of 4

Which of the following is the correct notation for the statement "as x approaches 3 from the left, f(x) decreases without bound"?

0 of 4 answered